Question

if p(t)=4t^4+ 5t^3-t^2+6 then p(1)=?​

Answer 1

Answer:

p(t) = 4(1)^4 + 5( 1) ^3 - ( 1) ^2 +6

= 4 + 5 - 1 + 6

14

Answer 2

Answer:

14

Step-by-step explanation:

$p(t)=4t^4+ 5t^3-t^2+6$

$p(1)=4(1)^4+ 5(1)^3-(1)^2+6 \\ = 4 + 5 - 1 + 6 = 14$