Question

If p(t)=4t4+5t3-t2+6 then p(1)=

Answer 1

Answer:

Value of p(1) = 14

Step-by-step explanation:

Given p(t) = 4t⁴+5t³-t²+6

Now,

Value of p(1)= 4×(1)⁴+5(1)³-1²+6

= 4+5-1+6

= 9+5

= 14

Therefore,.

Value of p(1) = 14

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