Question

If p(t) = t^3- 1, find the values of p(1),p(-1), p(0), p(2), p(- 2).​

Answer 1

Step-by-step explanation:

$p(t) = {t}^3 - 1$

p(1)= 1-1=0

p(-1)= -1-1 = -2

p(0)=0-1 = -1

p(2)= 2×2×2-1=8-1=7

p(-2)=(-2)^3-1=-8-1 = -9

Hope it helps you.

Answer 2

Answer:

p(1) = 0

p(-1) = -2

p(0) = -1

p(2) = 7

p(-2) = -9

Step-by-step explanation:

p(t) = t^3 - 1

p(1) = 1^3 - 1

         1 - 1 = 0

p(-1) = -1^3 - 1

          -1 - 1 = -2

p(0) = 0^3 - 1

         0 - 1 = -1

p(2) = 2^3 - 1

          8 - 1 = 7

p(-2) = -2^2 - 1

           -8 - 1 = -9