Question

if p(t)=t^3-1then find the values of p(1),p(-1),p(0),p(2),p(-2)​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$given \: \\ p(t) = {t}^{3} - 1 \\ put \: \\ t = 1 \\ p(1) = {1}^{3} - 1 \\ = 1 - 1 = 0 \\ put \: \\ t = - 1 \\ p( - 1) = { (- 1)}^{3} - 1 \\ = - 1 - 1 = - 2 \\ put \: \\ t = 0 \\ p(0) = {0}^{3} - 1 \\ = 0 - 1 = - 1 \\ put \: \\ t = 2 \\ p(2) = {2}^{3} - 1 \\ = 8 - 1 = 7 \\ put \: \\ t = - 2 \\ p( - 2) = {( - 2)}^{3} - 1 \\ = - 8 - 1 = - 9$

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