Question

if p (t)=t cube -1 find the values of p (1),p (-1),p (0),p (2),p (-2)​

Answer 1

Answer:

Let P (t) = t3 - 1

P (1) = 13 - 1 = 1 - 1 = 0

P (-1) = (-1 )3 -1 = -1 -1 = -2

P (0) = 03 -1 = 0 -1 = -1

P (-2) = (-2 )3 -1 = -8 -1 = -9

I hope it is helpful for you

Answer 2

Step-by-step explanation:

hi pushpa i hope you my answer is helpfull to you