Math, asked by komalathaneerati931, 5 months ago

if P(t)=t²-1.find the values of P(1),P(-1),P(2),P(0)​

Answers

Answered by tanvi692
2

Answer:

p(1)=0

p(-1)=0

p(2)=3

p(0)=-1

Step-by-step explanation:

p(1) =  {1}^{2}  - 1 \\  = 1 - 1 \\  = 0 \\  \\ p( - 1) =  { ( - 1)}^{2}  - 1 \\  = 1 - 1 \\  = 0 \\  \\ p(2) =  {2}^{2}  - 1 \\  = 4 - 1 \\  = 3 \\  \\ p(0) =  {0}^{2}  - 1 \\  = 0 - 1 \\  =  - 1

Answered by sahilmishra1916
3

Answer:

P(t) = t²-1

P(1) =(1)^2 - 1 = 1 - 1 = 0

P(-1) = (-1)^2 - 1 = 1 - 1 = 0

P(2) = (2)^2 - 1 = 4 - 1 = 3

P(0) = (0)^2 - 1 = 0 - 1 = -1

Step-by-step explanation:

here is your answer ☺️.

Similar questions