Question

if P(t)=t²-1.find the values of P(1),P(-1),P(2),P(0)​

Answer 1

Answer:

p(1)=0

p(-1)=0

p(2)=3

p(0)=-1

Step-by-step explanation:

$p(1) = {1}^{2} - 1 \\ = 1 - 1 \\ = 0 \\ \\ p( - 1) = { ( - 1)}^{2} - 1 \\ = 1 - 1 \\ = 0 \\ \\ p(2) = {2}^{2} - 1 \\ = 4 - 1 \\ = 3 \\ \\ p(0) = {0}^{2} - 1 \\ = 0 - 1 \\ = - 1$

Answer 2

Answer:

P(t) = t²-1

P(1) =(1)^2 - 1 = 1 - 1 = 0

P(-1) = (-1)^2 - 1 = 1 - 1 = 0

P(2) = (2)^2 - 1 = 4 - 1 = 3

P(0) = (0)^2 - 1 = 0 - 1 = -1

Step-by-step explanation:

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