If p(t) = t³ – 1, find the values of p(1), p(–1), p(0), p(2), p(–2).
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Hey There !
Given , p(t) = t³ - 1
Now, We are to find the values of p(1), p(–1), p(0), p(2), p(–2) .
So,
p(1) = (1)³ - 1 = 1 - 1 = 0
p(2) = 2³ - 2 = 8 - 2 = 6
p ( 0 ) = 0³ - 1 = 0 - 1 = -1
p(-1) = (-1)³ - 1 = -1-1 = -2
p(-2)³ = (-2)³ - 1 = -9
Hope helped!
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