if P term of an ap is a and q term is b what is the value of p+q term?
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Step-by-step explanation:
Given p times the pth term of an A.P is equal to q times the qth term of an A.P
ap = a+(p-1)d
aq = a+(q-1)d
ap+q = a+(p+q-1)d
p(a+(p-1)d) = q(a+(q-1)d)
p(a+(p-1)d) – q(a+(q-1)d) = 0
a(p-q) + (p2-q2)d + (q-p)d = 0
a(p-q) + (p-q)(p+q)d + (q-p)d = 0
a(p-q) + (p-q)d(p+q-1) = 0
Cancel (p-q) from both terms
a + (p+q-1)d = 0
So (p+q)th term = 0
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