Question

If p term of ap is q and q term of ap is p then (p+q) term is ?

Answer 1

Answer:0

Step-by-step explanation:

pth term=q

qth term=p

d=p-q/q-p

= -(q-p)/q-p

=-1

dn+(f-d)=p

dq+(f-d)=p

-q+(f+1)=p

f+1 =p+q

f=p+q-1

(p+q) th term

dn+(f-d)

=-(p+q)+(p+q-1+1)

=-(p+q)+p+q)

= 0

Answer 2

QUESTION:

If p term of ap is q and q term of ap is p then (p+q) term is ?

ANSWER:

We used the formula here ;

$nth \: term = a + (n - 1)d$

where

a = first term

d = common difference

GIVEN

pth term is q

qth term is ap

TO FIND :

(P+Q)th term?

$tp = a + (p - 1)d \\ q = a(p - 1)d.......(eq.1)$

$tq = a + (q - 1)d \\ p = a + (q - 1)d......(eq.2)$

On subtracting eq 2 and from Eq. 1 we get;

$(p - q)d = (q - p) \\ d = - 1$

$</u><u>\</u>h<u>u</u><u>g</u><u>e</u><u>\</u><u>r</u><u>e</u><u>d</u><u>{</u><u>d = - 1</u><u>}</u><u>$

putting d = -1 in equation 1.

WE get

$q = a(p - 1) - 1 \\ q = a - p + 1 \\ a = p + q - 1$

$</u><u>\</u><u>h</u><u>u</u><u>g</u><u>e</u><u>\</u><u>r</u><u>e</u><u>d</u><u>{</u><u>a = p + q - 1</u><u>}</u><u>$

now,

$t(p + q) = a + (p + q - 1)d \\ t(p + q) = (p + q - 1) - (p + q - 1) \\ t(p + q) = 0$

FINAL ANSWER :

$\huge\red{t(p + q) = 0}$

plz Mark as brainliest