If p
th term of an arithmetic progression is q and the q
th term is p, then find the n
th term of arithmetic
progression.
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Now use this to prove tn = (p + q − n). Thus, we obtain the value of the common difference to be –1. Hence, the first term of this arithmetic progression is (p + q – 1). Thus, it is proved that the nth term of the arithmetic progression is (p + q – n).
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