Question

If P Vector = Px i^ + Py j^ + Pz k^ and Q Vector = Qx i^ + Qy j^ + Qz k^ then find P Vector × Q Vector​

Answer 1

Answer:

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Explanation:

Let two vectors P and Q be P=Pxi+Pyj+Pzk and Q=Qxi+Qyj+Qzk. Now P+Q = (Px+Qx)i+(Py+Qy)j+Pz+Qz)k and P-Q=(Px-Qx)i+(Py-Qy)j+(Pz-Qz)k. The resultant of P+Q and P-Q is 2(Pxi+Pyj+Pzk) which has double the length of vector P same direction as P. So the angle between P and the resultant of P+Q and P-Q is zero.