Question

If p = x + 1 and (4p – 3)/2 – (3x + 2)/5 = 3/2, then the value of 2x – 2 is.

Answer 1

Answer:

0

Step-by-step explanation:

(4p-3)/2 - (3x+2)/5 = 3/2

(4 (x+1)-3)/2 -(3x+2)/5 = 3/2

(4x+4 - 3)/2 - (3x+2)/5 = 3/2

5(4x+1)/10 - 2(3x+2)/10 =3/2 ....(Cross multiplying the denominator)

(20x + 5) - (6x+4). = 3

_____________. __

10. 2

(14x + 1) / 10 = 3/2

14x + 1 = 3/2 × 10

14 x + 1 = 15

14 x = 14

x = 14/14

X = 1

Therefore, substituting the value of X as 1 in equation 2x-2 we get:

2x - 2 = 2(1) -2

2x - 2 = 0

Answer 2

• 2x - 2 = 0 .

Given :-

$\rightarrow\sf \: p \: = x \: + 1 \\ \\\rightarrow\sf \: \frac{4p - 3}{2} - \frac{3x + 2}{5} = \frac{3}{2}$

To Find :-

• 2x - 2 = ?

Solution :-

Let us assume that,

$\rightarrow\sf \: p \: = (x+ 1) - - \: equation(1) \\ \\\rightarrow\sf \: \frac{4p - 3}{2} - \frac{3x + 2}{5} = \frac{3}{2} \: - - equation(2)$

putting value of p from equation (1) in equation (2) we get,

$\rightarrow\sf \: \frac{4(x + 1) - 3}{2} - \frac{3x + 2}{5} = \frac{3}{2} \\ \\\rightarrow\sf \: \frac{4x +4 - 3}{2} - \frac{3x + 2}{5} = \frac{3}{2} \\ \\\rightarrow\sf \: \frac{4x + 1}{2} - \frac{3x + 2}{5} = \frac{3}{2}$

taking LCM of denominators in LHS now,

$\rightarrow\sf \: \frac{5(4x + 1) - 2(3x + 2)}{10} = \frac{3}{2} \\ \\\rightarrow\sf \: \frac{20x + 5 - 6x - 4}{10} = \frac{3}{2} \\ \\\: \rightarrow\sf\frac{14x + 1}{10} = \frac{3}{2}$

Cross - Multiply now,

→ 2(14x + 1) = 3 × 10

→ 28x + 2 = 30

→ 28x = 30 - 2

→ 28x = 28

dividing both sides by 28,

→ x = 1

therefore,

→ 2x - 2

→ 2 × 1 - 2

→ 2 - 2

→ 0 (Ans.)

Hence, the value of (2x - 2) is equal to zero .

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

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