if p(x)=(1+x/1-x) then p(0)+p(2)
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Answered by
1
p(0) = 1/1 = 1
p(2) = 3/(-1) = -3
p(0) + p(2) = 1-3 = -2
Answered by
2
Answer:
as p[0]=(1+x/1-x) as x=0. = (1/1)=1.
so, p[0]= 1 .
p[2]=(1+x/1-x)as x=2.= (1+2/1-2)=3/-1= -3.
so,p[2]= -3.
so, p[0]+p[2]= 1+(-3)= -2.
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