if p=x+1/x then the value of the p-1/p will be
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Solution 1) :-
→ p = x + (1/x)
→ p = (x² + 1)/x
→ 1/p = x/(x² + 1)
Putting both values now,
→ p - (1/p) = {(x² + 1)/x} - {x/(x² + 1)}
→ p - (1/p) = { (x² + 1)² - x² } / x(x² + 1)
→ p - (1/p) = { x⁴ + 1 + 2x² - x² } / (x³ + x)
→ p - (1/p) = (x⁴ + x² + 1) / (x³ + x) (Ans.)
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Solution 2) :-
→ p = (x + 1)/x
→ 1/p = x/(x + 1)
→ p - (1/p) = {(x + 1)/x} - {x / (x + 1)}
→ p - (1/p) = {(x + 1)² - x²} / x(x + 1)
→ p - (1/p) = { x² + 1 + 2x - x² } / (x² + x)
→ p - (1/p) = (2x + 1)/(x² + x) (Ans.)
Learn more :-
if a^2+ab+b^2=25
b^2+bc+c^2=49
c^2+ca+a^2=64
Then, find the value of
(a+b+c)² - 100 = ...
https://brainly.in/question/16231132
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6
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