Question

If p(x) = 10x – 4x^2 – 3, find p(1) and p(- 2)

Answer 1

Given, polynomial is

p(x) = 10x – 4x2 – 3

On putting x = 0,1 and – 2, respectively in Eq. (i), we get p(0) = 10(0)-4(0)2 -3 = 0-0-3= -3

p(1) = 10 (1) - 4 (1 )2 -3

= 10-4-3= 10-7= 3

and p(-2) =10 (-2)- 4 (-2)2 – 3

= -20-4×4-3 =-20-16-3=-39

Hence, the values of p(0), p(1) and p(-2) are respectively, -3,3 and – 39.

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Answer 2

Answer:

We have p(x)=10x−4x

2

−3

∴p(0)=10(0)−4(0)

2

−3

∴p(0)=0−0−3=−3

p(1)=10(1)−4(1)

2

−3

∴p(1)=10−4−3=3

And,

p(−2)=10(−2)−4(−2)

2

−3

∴p(−2)=−20−4(4)−3=−20−16−3=−39