Question

If p(x) = 12(x-1) and q(x) = 17(x + 1),
then h(x)= ...
(A) 1
(B) x-1
(C) x+1
(D) x2-1​

Answer 1

Answer:

x-1

Step-by-step explanation:

17x-17-(12x-12)

17x-17-12x+12

5x-5=x-1

Answer 2

Answer:

x-1

Step-by-step explanation:

12x-12,17x+17. 12x-12=0. 17x-17=0. =29x-29=0. =29x=29. x=1. =x-1