Question

if p(x)=2+1 , find the value of p(1)​

Answer 1

if p(x)=2+1 , find the value of p(1)

solve: Given p(x) = x³-x²+x+1

Given p(x) = x³-x²+x+1so, p(1) = (1)³-(1)²+1+1 = 2.

Given p(x) = x³-x²+x+1so, p(1) = (1)³-(1)²+1+1 = 2.and p(-1) = -1-1+1+1 = 0

Given p(x) = x³-x²+x+1so, p(1) = (1)³-(1)²+1+1 = 2.and p(-1) = -1-1+1+1 = 0therefore , p(1)+p(-1) = 2+0 = 2. and

Given p(x) = x³-x²+x+1so, p(1) = (1)³-(1)²+1+1 = 2.and p(-1) = -1-1+1+1 = 0therefore , p(1)+p(-1) = 2+0 = 2. and{p(1)+p(-1)}/2 = 2/2 = 1.