Question

If P=x^2+6,Q=3x^2-x+2,Rx^2-4x then findP-Q-R​

Answer 1

Answer:

Solve systems of equations by graphing. A system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system.

Step-by-step explanation:

Answer 2

Answer:

Given:-P=x²+6

Q=3x²–x+2

R=X²–4x

To find:-P–Q–R

Step-by-step explanation:

=P–Q–R

=x²+6–(3x²–x+2)–(x²–4x)

=x²+6–3x²+x–2–x²+4x

= –3x²–5x–4

=–(3x²+5x+4)

=This can't be factorized therefore the correct answer this.

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