Question

If p(x) = 2+ x/2+x²-x³/3 then (p-1)is

Answer 1

we consider x means (-1)

Answer 2

Complete question is If p(x) = 2+ x/2+x²-x³/3 then p(-1)

Answer:

Required value of p(-1) is$\frac{17}{6}$

Step-by-step explanation:

Given,$p(x) = 2 + \frac{x}{2} + {x}^{2} - \frac{ {x}^{3} }{3}$

p(x) is a function.

Here we want to find p(-1)

If we will put (-1) instead of x then we can find p(-1)

So,P(-1)=$2 + \frac{ - 1}{2} + { (- 1)}^{2} - \frac{ {( - 1)}^{3} }{3} = 2 - \frac{1}{2} + 1 + \frac{1}{3} = 3 - \frac{1}{6} = \frac{17}{6}$

So value of p(-1) is $\frac{17}{6}$

By this method we can find p(x) for any value of x.

For example,

If x=0 then $p(0) = 2 + \frac{0}{2} + {0}^{2} - \frac{ {0}^{3} }{3} = 2$

and if x=1 then $p(1) = 2 + \frac{1}{2} + {1}^{2} - \frac{ {1}^{3} }{3} = 2 + \frac{1}{2} + 1 - \frac{1}{3} = 3 + \frac{1}{6} = \frac{19}{6}$

e.t.c.