Question

If p(x) = 2x+1 then the value of p(1/root2) is

Answer 1

Answer:

let 1 be x

so

p(x / root 2 ) = root 2

so

p( root 2 ) = 2 root 2 + 1

Answer 2

$\displaystyle \sf{If \: \: p(x) = 2x + 1 \: \: then \: \: p \bigg( \frac{1}{ \sqrt{2} } \bigg) = \sqrt{2} + 1}$

Given :

$\displaystyle \sf{ p(x) = 2x + 1 }$

To find :

$\displaystyle \sf{p \bigg( \frac{1}{ \sqrt{2} } \bigg) }$

Solution :

Step 1 of 2 :

Write down the given polynomial

Here the given polynomial is

p(x) = 2x + 1

Step 2 of 2 :

Find the value

$\displaystyle \sf{ p(x) = 2x + 1 \: \: }$

$\displaystyle \sf{ \implies \: p \bigg( \frac{1}{ \sqrt{2} } \bigg) = 2 \times \frac{1}{ \sqrt{2} } + 1}$

$\displaystyle \sf{ \implies \: p \bigg( \frac{1}{ \sqrt{2} } \bigg) = \sqrt{2} + 1}$

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