If P(x)=2x^2-3x+1, then(a) What number is P(1) ?(b) Write a first degree polynomial which is a factor of P(x).
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Answer:
(a) 0
(b) (x - 1)
Step-by-step explanation:
p(x) = 2x² - 3x + 1
(a) p(1) = 2(1)² - 3(1) + 1
= 2 - 3 + 1
= -1+1 = 0
p(1) = 0
(b) From (a) we have that p(1) = 0
Now as by factor theorem if the zero of any linear polynomial when putted as (for example) x in p(x) gives us 0 then the linear polynomial is a factor of p(x)
So from (a),
(x - 1) is a first degree polynomial which is a factor of p(x)
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