Question

If p(x)=2x^3-3x^2+x-4 then find p(-2) value

Answer 1

Answer:

p(2)=2^3+3×2^2-2×2+4

p(2)=8+12-4+4

p(2)=24-4

p(2)=20

p(-2)=-2^3+3×-2^2-2×-2+4

p(-2)=-8+12+4+4

p(-2)=20-8

p(-2)=12

p(0)=0^3+3×0^2-2×0+4

p(0)=0+0+0+4

p(0)=4

Step-by-step explanation:

Answer 2

Answer :-

p(-2) = -34

Solution :-

p(x)=2x³-3x²+x-4

p(-2) = 2(-2)³-3(-2)²+(-2)-4

= 2(-8)-3(4)-2-4

= -16-12-6

= -34