Question

If p(x)=2x^3-3x^2-x find p(-2)

Answer 1

hey the answer is. . . .

p (-2 )= 2 ×-2^3 - 3 ×- 2^2 - (-2)

= -16 - 12 + 2

= - 26

hope it helps uu frnd.

Answer 2

$p(x) = {2x}^{3} - {3x}^{2} - x \\ = > p( - 2) = 2{ (- 2)}^{3} - 3{( - 2)}^{2} - ( - 2) \\ = > p( - 2) = 2 \times (- 8) - 3 \times 4 + 2 \\ = > p( - 2) = - 16 - 12 + 2 \\ = > p( - 2) = - 26 \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ hope \: it \: helps \: u.......... \\ \\ \\ \\ \\ \\ \\ \\ \\ plz \: mark \: as \: brainliest$