Question

If p (x) = 2x^3 + 3x -5 , then find p (-2)

Answer 1

⠀⠀⠀⠀⠀$\huge\underline{ \mathrm{ \red{QueS{\pink{tiOn}}}}}$

If p (x) = 2x^3 + 3x -5 , then find p (-2)

_______________________________________________

⠀⠀⠀⠀⠀⠀$\huge{ \underline{ \purple{ \bold{ \underline{ \mathrm{AnS{\blue{weR }}}}}}}}$

$\large\underline{ \underline{ \green{ \bold {Given}}}} = >$

p(x) =

$\bf2 {x}^{3} + 3x - 5$

______________

$\large\underline{ \underline{ \green{ \bold{To\:Find}}}} = >$

p(-2)

______________

$\large\underline{ \underline{ \green{ \bold{solution}}}} = >$

$\bf 2 \times( - 2) {}^{3} + 3 \times ( - 2) - 5 \\ = > \bf - 16 - 6 - 5 \\ = > \bf- 27$

______________________________

hops this may help you

⠀⠀⠀⠀⠀⠀⠀⠀$\huge{ \pink{ \ddot{ \smile}}}$

⠀⠀⠀⠀⠀⠀$\huge \mathfrak{ \blue { \bigstar{thanks}}}$

Answer 2

Answer:

put value of - 2 in place of x

2 ( - 2 ) ^ 3 + 3 × ( - 2 ) - 5

2 × -8 + ( - 6 ) - 5

- 16 - 11

= - 27