Question

if p(x)= 2x^3-5x^2+2x find p(a),p(2),p(-1)​

Answer 1

Answer:

p(a) = 2$a^{3}$ -5$a^{2}$ +2a

p(2) = 0

p(-1) = -9

Step-by-step explanation:

put a at the place of x

then we get p(a) = 2$a^{3}$ -5$a^{2}$ +2a

similarly

p(2) = 2×2³ - 5×2² + 2×2 =16-20+4 = 0

p(-1) = 2×(-1)³ - 5×(-1)² +2×(-1) = -2-5-2 = -9

Answer 2

Answer:

Step-by-step explanation:

a. - p(a)=2*(a)^3-5*(a)^2+2*a

            = 2a^3-5a^2+2a

b. - p(2)=2*(2)^3-5*(2)^2+2*2

            =16-20+4

            =0

c. - p(-1)=2*(-1)^3-5*(-1)^2+2*(-1)

            =-2-5-2

            =-9