if p(x) = 2x cube - x square + 3x +1 , find the value of p(-1) + p(1) - p(2)
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2x^3-x^2+3x+1
p(x)
i)p(-1)=2(-1)^3-(-1)^2+3(-1)+1
=2*-1-1+(-3)+1
=-2-1-3+1
=-5
ii)p(1)=2(1)^3-(1)^2+3*1+1
=2*1-1+3+1
=2-1+3+1
=5
iii)p(2)=2(2)^3-(2)^2+3*2+1
=2*8-4+6+1
=16-4+6+1
=19
So, p(-1)+p(1)-p(2)
=-5+5-19
=-19 Ans.
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p(x)
i)p(-1)=2(-1)^3-(-1)^2+3(-1)+1
=2*-1-1+(-3)+1
=-2-1-3+1
=-5
ii)p(1)=2(1)^3-(1)^2+3*1+1
=2*1-1+3+1
=2-1+3+1
=5
iii)p(2)=2(2)^3-(2)^2+3*2+1
=2*8-4+6+1
=16-4+6+1
=19
So, p(-1)+p(1)-p(2)
=-5+5-19
=-19 Ans.
Mark as brainliest
Answered by
1
p(x)=2x³-x²+3x+1
p(-1)=2(-1)³-(-1)²+3(-1)+1
=-2-1-3+1
= -5
p(1)=2(1)³-(1)²+3(1)+1
=2-1+3+1
=5
p(2)=2(2)³-(2)²+3(2)+1
=16-4+6+1
=19
p(-1)+p(1)-p(2)
-5+5+19
=19
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