Question

If p(x)=2x² - 3x, then find p( root 2 )
can someone answer this fast plss​

Answer 1

Answer:

here

Step-by-step explanation:

p(x)=2x^2-3x

then

p(√2) = 2*√2*√2-3*√2

4-3√2 is the answer

Answer 2

Answer:

$p( \sqrt{2}) = 4 - 3 \sqrt{2}$

Step-by-step explanation:

$p(x) = 2 {x}^{2} - 3x \\ p( \sqrt{2} ) = 2 \times { (\sqrt{2}) }^{2} - 3 \times \sqrt{2} \\ = 2 \times 2 - 3 \sqrt{2} \\ = 4 - 3 \sqrt{2}$