Question

if p(x) =2x³-5x+3 and q(x)=x-1 then the remainder when p(x) is divided by q(x) will be​

Answer 1

$\sf \red{q(x) = x - 1} \\ \sf{x - 1 = 0} \\ \sf{x = 0 + 1 } \\ \sf{x = 1}$

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$\sf \red{p(x) = {2x}^{3} - 5x + 3 } \\ \sf{ \implies \sf{ 2 \times {1}^{3} - 5 \times 1 + 3}} \\ \implies \sf{2 - 5 + 3} \\ \implies \sf{ - 3 + 3} \\ \implies \sf{0} \\ \sf \red\therefore \sf \red{The \: remainder \: is \: 0 }$