Question

if p(X)= 2x³+ax²+3x-5 and q(X) =x³+x²-4x+a leave the same remainder when divided by (x-2) show that a=-13/3​

Answer 1

Answer:

Step-by-step explanation:

p(x)= 2x³+ax²+3x-5

and q(x) =x³+x²-4x+a

Putting x-2=0

x=2

Thus remainder

p(2)=q(2)

2*2³+a*2²+3*2-5=2³+2³-4*2+a

2*8+4a+6-5=8+4-8+a

16+4a+1=4+a

3a=4-17=-13

a=-13/4