Question

If p(x)=2x⁴-5x³+8a+1 leaves the remainder 2 you when divided by x-1. Find the value of a.​

Answer 1

Answer:

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g(x)=0

x-1=0

x=1

p(x)=2x⁴-5x³+8a+1

p(1)=2(1)⁴-5(1)+8a+1

=2-5+8a+1

=-2+8a

p(x)=0

-2+8a=0

8a=2

a=2/8

a=1/4

Hope it will help you...

Answer 2

$\large{ \boxed{ \underline{ \overline{ \mathfrak{ \sf{ANSWER: - }}}}}}$

g(x)=0

x-1=0

x=1

p(x)=2x⁴-5x³+8a+1

p(1)=2(1)⁴-5(1)+8a+1

=2-5+8a+1

=-2+8a

p(x)=0

-2+8a=0

8a=2

a=2/8

a=1/4

Hope it will help you...

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