if p(x)=3-2x^3+3x^2 then find the p(-2)
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Answer:
p(-2)=31
Step-by-step explanation:
given ,
p(x)=3-2x^3+3x^2
p(-2)= 3 -2(-2)^3+3(-2)^2
=3+16+12
=31
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