Question

If P(x) = √3 x²-3x+2 find the
value of P(√3)​

Answer 1

Answer:

Step-by-step explanation

P(x)=root 3x^2-3x+2

P(root3)= root3(root3)^2-3(root3)+2

3root3-3root3+2=0

0+2=2

Answer 2

Answer:

p(√3) = 2

Note:

★ If the expression for a polynomial p(x) is given , then to fine p(a) we just need to put x = a every where in the expression of p(x) .

Solution:

Given : p(x) = √3x² - 3x + 2

To find : p(√3) = ?

Now,

We have ,

p(x) = √3x² - 3x + 2

Let's find p(√3) on putting x = √3 everywhere in the expression of p(x) .

Thus,

=> p(x) = √3x² - 3x + 2

=> p(√3) = √3•(√3)² - 3•(√3) + 2

=> p(√3) = 3√3 - 3√3 + 2

=> p(√3) = 2

Hence,

The required value of p(√3) is 2 .