if p(x)=3x^2-6x+8 then find sum of zeros
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Solution
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We can see at x=1,f(1)=0
∴
(x−1))
x
3
−3x
2
−6x+8
(x
2
−2x−8
x
3
−x
2
________________
−2x
2
−6x
−2x
3
+2x
________________
−8x+8
−8x+8
________________
∴f(x)=(x−1)(x
2
−2x−8)
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