Question

if p(x)=3x^3-2x^2-x +4, then find the value of p(-1)+p(1)​

Answer 1

Step-by-step explanation:

solution : Given that

p(x)=3x^3-2x^2-x +4

p(-1)+p(1) = 3(-1)^3-2(-1)^2-(-1) +4

+3(1)^3-2(1)^2-1 +4

= 3(-1)-2(1)+1+4+3(1)-2(1)-1+4

= -3-2+1+4+3-2-1+4

= 8

p(-1)+p(1) = 8