Math, asked by sajithasajeev31, 17 days ago

if p(x)=3x²-2x+1, find p(-1),p(0),p(1)​

Answers

Answered by heheman123
1

Answer:

p(-1) =  6

p(0) = 1

p(1) = 2

Step-by-step explanation:

p(-1) = 3(-1)^2 -2(-1) + 1

= 3 + 2 + 1

= 6

p(0) = 3(0)^2 -2(0) + 1

=0 + 0 + 1

= 1

p(1) = 3(1)^2 -2(1) + 1

= 3 - 2 + 1

= 2

Answered by saxenaprisha5
1

Answer:

Step-by-step explanation:

3(-1)^2 -2(-1)+1

= 3 +2 +1

=6

3(0)^2 -2(0)+1

= 0+0+ 1

=1

3(1)^2 -2(1)+1

=3-2+1

=2

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