Question

If p(x)=3x²-2x+1 then what is ,p(0),p-1)..

Answer 1

Answer:

Hence,p(0)=1 and p(-1)=6

Step-by-step explanation:

Given:

p(x)=3x^2-2x+1

Here,

p(0)=3(0)^2-2(0)+1

=0-0+1

=1

.°.p(0)=1

Now,

p(-1)=3(-1)^2-2(-1)+1

=3+2+1

=6

.°.p(-1)=6

Answer 2

Given

We have given function p(x) = 3x²-2x+1

To find

We have to find p(0),p(-1)

$\sf\huge {\underline{\underline{{Solution}}}}$

Note : Any change in p(x) will cause a change in the function.

Now ,our function is p(x) and we have to find f(0) & p(-1) now compare the coefficient of p(x) with f(0) & p(-1), we find x=0 & x= -1

So,we have to find the value of p(x) at x=0 , -1

At x=0

p(0)= 3(0)²-2(0)+1

p(0)= 0-0+1

p(0)=1

At x=-1

p(-1)= 3(-1)²-2(-1)+1

p(-1)= 3+2+1

p(-1)= 6

∴ P(0) = 1 & P(-1)= 6

More information=>

➥The above function is a linear equation as highest power is 1.

➥p(x)=y here ,f is the function and x is an input which gives output say 'y'.

➥We can find infinite number of output of p(x) by putting infinite number of values into p(x).