Question

If p(X )=3x²-x-4, find the values of p(1),p(2),p(-1),p(-2)​

Answer 1

Answer:

put X=1 to find

p(1) = 3(1)^2-1-4

P(1) = 3-1-4

p(1) = 3-5=

P(1) = -2

find all in same way ... put x=2 to find P(2)

put x=-1 to find P(-1)= 3×(-1)^2 - (-1) -4

p(-1) = 3+1-4 =4-4 =0

in the same way find next

Answer 2

AnsweR :-

P(x) = 3x² - x - 4

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p(1) = 3(1)² - (1) - 4

p(1) = 3 - 1 - 4

p(1) = -2

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P(2) = 3(2)² - (2) - 4

P(2) = 12 - 2 - 4

P(2) = 6

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P(-1) = 3(-1)² - (-1) - 4

P(-1) = 3 + 1 - 4

P(-1) = 0

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P(-2) = 3(-2)² - (-2) - 4

P(-2) = 12 + 2 - 4

P(-2) = 10

Procedure :-

$\implies$ This question is from the chapter polynomials, in the first case we have to put 1 in place of x and the we have equate the whole expression and hence, the final answer is -2.

$\implies$ In the second case we will put the 2 in place of x and then again we will equate the whole expression and hence, the answer is 6.

$\implies$ In the third case we will put -1 in place of x and then we will equate the whole expression again, but, we have put positive sign in place of negetive because (-)(-) = +, and hence, the final answer is 0.

$\implies$ In the fourth case we will do the same as we have done in third equation, and Hence, the final answer is 10.

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