If p(x)=3x³-2x²-x+4, then find the value of p(-1).
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p(-1)=3(-1)^3-2(-1)^2-(-1)+4
=-3-2+1+4
=-5+5
=0
=-3-2+1+4
=-5+5
=0
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Answered by
2
Answer:
p(-1) = 3x^3 - 2x^2 - x + 4
p(-1) = 3(-1)^3 - 2(-1)^2 - (-1) + 4
= -3 - 2 + 1 + 4
= -5 + 5
= 0
The value is 0
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