Question

If P(x)=3x³=5x²–11X–3 then find p (0) and P(-1).​

Answer 1

Answer:

$p(x) = 3 {x}^{3} + 5 {x}^{2} - 11x - 3 \\ \\ \\ \\ p(0) = 3 \times {0}^{3} + 5 \times {0}^{2} - 11 \times 0 - 3 \\ \\ \\ \\ \\ \\ \\ \\ = - 3 \\ \\ \\ \\ \\ \\ \\ \\ p( - 1) = 3 \times {( - 1)}^{3} + 5 \times {( - 1)}^{2} - 11 \times ( - 1) - 3 \\ \\ \\ \\ \\ = - 3 + 5 + 11 - 3 \\ \\ \\ \\ \\ \\ = 10$

Answer 2

Answer:

................ p(0) = -3

P(-1) = 10 .................