If p(x)=3x3-5x2+7x-11. Is p(o)+p(1)=P(2)
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Step-by-step explanation:
p(X)=3x^3-5x^2+7x-11
p(0)=3(0)^3-5(0)^2+7(0)-11
=0-0+0-11
=-11
p(1)=3(1)3-5(1)^2+7(1)-11
=-3+7-11
=-6
p(2)=3(2)^3-5(2)^2+7(2)-11
=24-20+14-11
=7
we have to check whether p(0)+p(1)=p(2)
-11+(-6)=7
-11-6=7
-17=7
here we can say that p(0)+p(1)=p(2) is not equal
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