Question

if p(x) = 4+3x -x² + 5x find p(0)​

Answer 1

Answer:

Step-by-step explanation:

P(x) = 5x^3-x^2+3x+4

Put x = 0 then

=> P(0) = 5(0)^3-(0)^2+3(0)+4

=> P(0) = 5(0)-0+0+4

=> P(0) = 0-0+0+4

=> P(0) = 4

Therefore , P(0) = 4

Answer 2

Answer:

p(x)= -x²+8x+4

p(0)=0+0+4

p(0)=4

thus

at x=0

p(x)=4