Question

if p(x)=4+3x-x²+5x³, find: (I)p(0)
(ii) p(2) (iii) p(-1)​

Answer 1

Step-by-step explanation:

p(0) = 4+ 3(0)-0²+5(0)³= 4+0-0+0 = 4

p(2) = 4 +3(2)-(2)²+ 5(2)³ = 4+6-4+5(8) = 4+6-4+40= 46

p(-1) = 4 +3(-1)-(-1)²+5(-1)³= 4-3-1-5 = 4-9 = -5

Answer 2

Step-by-step explanation:

Given :-

p(x)=4+3x-x^2 +5x^3

To find:-

find the following :

(i)p(0)

(ii) p(2)

(iii) p(-1)

Solution :-

.

Given Polynomial is p(x)=4+3x-x^2 +5x^3

On writing it in the standard form

=> P(x) = 5x^3-x^2+3x+4

(i)p(0):-

P(x) = 5x^3-x^2+3x+4

Put x = 0 then

=> P(0) = 5(0)^3-(0)^2+3(0)+4

=> P(0) = 5(0)-0+0+4

=> P(0) = 0-0+0+4

=> P(0) = 4

Therefore , P(0) = 4

(ii) p(2) :-

P(x) = 5x^3-x^2+3x+4

Put x = 2 then

=> P(2) = 5(2)^3-(2)^2+3(2)+4

=> P(2) = 5(8)-4+6+4

=> P(2) = 40-4+6+4

=> P(2) = 40+6

=> P(2) = 46

Therefore , P(2) = 46

(iii) p(-1):-

P(x) = 5x^3-x^2+3x+4

Put x = -1 then

=> P(-1) = 5(-1)^3-(-1)^2+3(-1)+4

=> P(-1) = 5(-1)-(1)+(-3)+4

=> P(-1) = -5-1-3+4

=> P(-1) = -9+4

=> P(-1) = -5

Therefore , P(-1) = -5

Answer:-

The value of P(0) = 4

The value of P(2) = 46

The value of P(-1) = -5