If p(x) = 4 x^2 -3x x^3 +5 and q(x) = x^2 + 2 x +4 , then p(x) - q(x) is ..... answer quickly
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Step-by-step explanation:
first ,find the zeroes of the quadratic polynomial 2x²-9x + 4.
2x² - 9x + 4 = 0
2x² -8x -x + 4 = 0
2x (x - 4) -1 (x - 4) = 0
(2x - 1) (x - 4) = 0
x = 1/2 or x = 4
As we have given condition, the zeroes of the polynomial x² + px + q
are double in the value to the zeroes Of 2x²-9x + 4
let the zeros of the polynomial
x² + px + q are α and β
α = 2 (1/2) = 1
β = 2 (4) = 8
compare the equation x² + px + q
with standard form of quadratic equation ax² + bx + c = 0
there for, a = 1 , b = p, c = q
we know the relation between coefficients and roots of the quadratic polynomial
α + β =- b/a
(1) + (8) = -p /1
9= -p
p = -9
and (α .β) = c/a
( 1 x 8 ) = q / 1
8 = q
Q=8
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