Question

if p(x)=4x^2-5x+3,find p(0),p(-1),p(2),p(3)​

Answer 1

Given - 4x²-5x+3

To find - p(0),p(-1),p(2),p(3)

Solution -

p(x) =4x²-5x+3

p(0)=4(0)²-5(0)+3

p(0)=4×0-5×0+3

p(0)=0-0+3

p(0)=3

p(x)=4x²-5x+3

p(-1)=4(-1)²-5(-1)+3

p(-1)=4×1+5+3

p(-1)=4+5+3

p(-1)=12

p(x)=4x²-5x+3

p(2)=4(2)²-5(2)+3

p(2)=4×4-10+3

p(2)=16-10+3

p(2)=19-10

p(2)=9

p(x)=4x²-5x+3

p(3)=4(3)²-5(3)+3

p(3)=4×9-15+3

p(3)=36-15+3

p(3)=39-15

p(3)=24