Question

If p(x)= 5 - 4x + 2x”, find (1) p(0), (ii) p(3), (iii) p(-2)​

Answer 1

Answer:

$= > p(x) = 2 {x}^{2} - 4x + 5$

$= > p(0) = 2( {0)}^{2} - 4 \times 0 + 5 = 0 - 0 + 5 = 5$

$= > p(3) = 2 {(3)}^{2} - 4 \times 3 + 5 = 18 - 12 + 5 = 11$

$= > p(2) = 2 {(2)}^{2} - 4 \times 2 + 5 = 8 - 8 + 5 = 5$

Hope this answer helps you ^_^ !

Answer 2

(i)p(0)=5-4(0)+2(0)²

p(0)=5-0+0=5

(oi)p(3)=5-4(3)+2(3)²

p(1)=5-12+18=11

(3)p(-2)=5-4(-2)+2(-2)²

p(-2)=5+8+8=21

hopw it helps you buddy