Question

If p(x)=5-4x+2x² find (1)p(0) (2) p(3) (3)p(-2)

Answer 1

Hii friend,

P(X) = 5-4X+2X² => 2X²-4X+5

(1) P(0) = 2 × (0)² - 4 × 0 +5 = 0-0+5 = 5

(2) P(3) = 2 × (3)² - 4 × 3 +5 = 2 × 9 -12 +5 = 18-12+5 = 11

(3) P(-2) = 2 × (-2)² - 4 × -2 + 5 = 2 × 4 +8 +5 = 8+8+5 = 21.


HENCE,

P(0) = 5 , P(3) = 11 AND P(-2) = 21.


HOPE IT WILL HELP YOU..... :-)

Answer 2

Given:

We have an quadratic equation which is  p(x)=5-4x+2x².

To Find:

We have to find the value of P(0),P(3),P(-2)

Step-by-step explanation:

We have given a quadratic equation which is  P(x)=5-4x+2x².

We are calling it a quadratic equation because the highest power of the equation is the 2.

• 1) We will find P(0)

        We have  P(x)=5-4x+2x².

        We can find the P(0) by replacing the x by 0 thus we will get

         $P(x)=5-4x+2x^2\\P(0)=5-4(0)+2(0)^2$

• Now simplify the above equation we get

      $P(0)=5-4(0)+2(0)^2=5-0=5$

• 2) Now We will find P(3)

       We have  P(x)=5-4x+2x².

• We can find the P(3) by replacing the x by 3 thus we will get

        $P(x)=5-4x+2x^2\\P(3)=5-4(3)+2(3)^2$

• Now simplify the above equation we get

       $P(3)=5-4(3)+2(3)^2=5-12+18=23-12=11$

• 3) Now We will find P(-2)

        We have  P(x)=5-4x+2x².

• We can find the P(-2) by replacing the x by -2 thus we will get

       $P(x)=5-4x+2x^2\\P(-2)=5-4(-2)+2(-2)^2$

• Now simplify the above equation we get

       $P(-2)=5-4(-2)+2(-2)^2=5+8+8=21$

Hence we get the P(0)=5,P(3)= 11,P(-2)=21.