Question

If P(x) = 5 x^2 - 4 x + 5 , find p(1) + p(-1) + p(0)

Answer 1

Answer:

p(x) = 5x^2 - 4x + 5

p(1) = 5(1)^2 -4(1) + 5

= 5 - 4 + 5

= 6

p(-1) = 5 (-1)^2 - 4(-1) + 5

= 5 + 4 + 5

= 14

p(0) = 5(0)^2 - 4(0) + 5

= 0 - 0 + 5

= 5

6 + 14 + 5

= 25

hope it helps

Answer 2

Given,

p(x) = 5x²-4x+5

To find,

The value of p(1) + p(-1) + p(0).

Solution,

The value of p(1) + p(-1) + p(0) will be 25.

We can easily solve this problem by following the given steps.

According to the question,

p(x) = 5x²-4x+5

Now, first put the value of x as (1) in this polynomial:

p(1) = 5(1)²-4(1)+5

p(1) = 5(1)-4+5

p(1) = 5-4+5

p(1) = 10-4

p(1) = 6

Now, put the value of x as (-1) in the polynomial:

p(-1) = 5(-1)²-4(-1)+5

p(-1) = 5(1)+4+5

p(-1) = 5+4+5

p(-1) = 14

Now, put the value of x as 0 in the polynomial:

p(0) = 5(0)²-4(0)+5

p(0) = 5(0)-0+5

p(0) = 0-0+5

p(0) = 5

Now, putting these three values in the following expression:

p(1) + p(-1) + p(0)

6+14+5

20+5

25

Hence, the value of p(1) + p(-1) + p(0) is 25.