If
P(x)=(5x+3)^2
Q(x)=ax^2+bx+bc
are equivalent. Find 'ab+c'
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Step-by-step explanation:
Discriminant of P(x) ;D`=b^2-4ac and that of Q(x) D"=d^2+4acWe are given that ac not equal to 0 .thus ac can either be -ve or + ve.If ac is -ve D` is +ve while D" can be -ve or + veAnd if ac is +ve D" is + ve and D` can be + ve or - ve.For both the cases P(x)Q(x)=0 has at least two real roots
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Answer:
759
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