Question

if p(x) = 5x^3-2x^2+3x-2 then find the values of p(0)p(1) and p(2)​

Answer 1

$P(x)=5x^3-2x^2+3x-2\\\\P(0)=5(0)^3-2(0)^2+3(0)-2\\P(0)=-2\\\\P(1)=5(1)^3-2(1)^2+3(1)-2\\P(1)=5-2+3-2\\P(1)=4\\\\P(2)=5(2)^3-2(2)^2+3(2)-2\\P(2)=40-8+6-2\\P(2)=40-4\\P(2)=36$

Answer 2

Answer:

Taking p(0) = 5×0^3-2×0^2+3×0-2

=0-0+0-2

P(0) = -2

Taking p(1)

= 5×1^3-2×1^2+3×1-2

= 5-2+3-2

= 5-5-2

= -2

Taking p(2)

=5×2^3-2×2^2+3×2-2

=40-8+6-2

40-4

= 36

So values of p(0) = -2

P(1) = -2

P(2) = 36

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Step-by-step explanation: