Question

if p(x) = 6x^3+5x^2-3x+2 find p(-1)

Answer 1

If p = (-1),
Then,
$p( - 1) = 6( - 1) ^{3} + 5 ( - 1) ^{2} - 3( - 1) + 2$
$\: \: \: \: \: \: = 6( - 1) + 5(1) + 3 + 2$
= -6 + 5 + 3 +2
= -6 + 10
= 4

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Answer 2

Answer:

p(x) =

$6x ^{3} + 5x {}^{2} - 3x + 2$

p(-1)

$6( - {1}^{3} + 5 ( { - 1) }^{2} - 3 ( - 1) + 2$

p(-1)

$- 6 + 5 + 3 + 2$

p(-1)

$4$

p(-1) is 4